Problems on trains - Quantitative Aptitude - Aptitude question and answers

Explanation / Important formulas:

  • km/hr to m/s conversion: a km/hr = (a X 5/18) m/s
  • m/s to km/hr conversion: a km/hr = (a X 18/5) km/hr
  • Time taken by a train of length metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres
  • Time taken by a train of length metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres
  • Suppose two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u – v) m/s
  • Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s
  • If two trains of length metres and b metres are moving in opposite directions at u m/s and v m/s, then: their relative speed is = (u – v) m/s
  • Suppose two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s
  • If two trains of length metres and b metres are moving in opposite directions at u m/s and v m/s, then: The time taken by the trains to cross each other = (a+b) / (u+v) sec
  • The time taken by the faster train to cross the slower train = (a+b) / (u-v) sec

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Problems on trains - Question and Answers

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