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Instructions for Jumpwhere Aptitude Contest – November 2024:
- You can select only one option at a time.
- You can take the QUIZ multiple times.
- Each question will carry 100 points.
- There are altogether 35 questions.
- After finishing the test, you will get a score message as shown below.
- If you score more than 90% you will get a unique code and email id along with the score message.
- Take the screenshot of the entire page containing the message along with the unique code generated.
- Lucky winners will get exciting goodies/gift from JUMPWHERE. The final decision will be taken by JUMPWHERE TEAM itself.
- This contest is available only till 30-Nov-2024 12:00 PM.
- Don’t forget to Like and Follow us on facebook for all the updates.
Jumpwhere Aptitude Contest – November 2024:
Quiz Contest - November
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Question 1 |
In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
A | 5040 |
B | 480 |
C | 360 |
D | 720 |
Question 1 Explanation:
The word 'LEADING' has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
Question 2 |
A child went 90 m in the East to look for his father, then he turned right and went 20 m. After this he turned right and after going 30 m he reached to his uncle's house. His father was not there. From there he went 100 m to his north and met his father. How far did he meet his father from the starting point?
A | 140 m |
B | 100 m |
C | 260 m |
D | 80 m |
Question 3 |
The time taken by a boat to travel upstream is twice the time taken by it to travel downstream. If the speed of the boat in still water is 9 kmph, find the rate of current?
A | 2.5 kmph |
B | 3 kmph |
C | Data insufficient |
D | 2 kmph |
Question 3 Explanation:
The downstream speed should be twice the upstream speed
9+x = 2*(9-x)
X= 3
9+x = 2*(9-x)
X= 3
Question 4 |
What is the probability of getting a sum 9 from two throws of a dice ?
A | 1/6 |
B | 1/9 |
C | 1/8 |
D | 1/12 |
Question 4 Explanation:
In two throws of a dice, n(S) = (6 x 6) = 36
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}
Therefore, n(E) / n(S) = 4 / 36 = 1/ 9
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}
Therefore, n(E) / n(S) = 4 / 36 = 1/ 9
Question 5 |
A wooden cube of volume 216 m3 is cut into smaller cubes each of whose side measure 2m. How many smaller cubes have been formed?
A | 54 |
B | 6 |
C | 108 |
D | 27 |
Question 5 Explanation:
Volume of the smaller cubes = a cube = 8m cube
Number of cubes = 216/8 = 27
Number of cubes = 216/8 = 27
Question 6 |
Statement: Exporters in the capital are alleging that commercial banks are violating a Reserve Bank of India directive to operate a post shipment export credit denominated in foreign currency at international rates from January this year.
Courses of Action:
I) The officers concerned in the commercial banks are to be suspended.
II) The RBI should be asked to stop giving such directives to commercial banks.
A | Only II follows |
B | Neither I nor II follow |
C | Both I and II follow |
D | Only I follows |
E | Either I or II follows |
Question 6 Explanation:
The statement mentions that the commercial banks violate a directive issued by the RBI.
The remedy is only to make the banks implement the Act.
So, none of the courses follows
The remedy is only to make the banks implement the Act.
So, none of the courses follows
Question 7 |
Statement : Should the tuition fees in all post graduate courses be hiked considerably ?
Arguments :
I. Yes. This will bring some kind of seriousness among the students and will improve quality.
II. No. This will force the meritorious poor students to stay away from post-graduate courses.
A | Either I or II is strong |
B | Only argument II is strong |
C | Neither I nor II is strong |
D | Both I and II are strong |
E | Only argument I is strong |
Question 7 Explanation:
Clearly seriousness among the students is not because of fees but second argument is strong
Question 8 |
Find the simple interest on Rs. 5000 at a certain rate if the compound interest on the same amount for 2 years is Rs. 253.125?
A | Rs. 100 |
B | Rs. 400 |
C | Rs. 500 |
D | Rs. 250 |
Question 8 Explanation:
Let the rate of interest be r
5000[1+ r /100]2 = 5000 + 253.125
[1+ r /100]2 = 5253.125 / 5000
Solving which gives
[1+ r/100]2 = 1681 / 1600
1+ r/100 = 41 / 40
r = 2.5
Therefore, SI = 5000 * 2 * 2.5 / 100 = Rs. 250
5000[1+ r /100]2 = 5000 + 253.125
[1+ r /100]2 = 5253.125 / 5000
Solving which gives
[1+ r/100]2 = 1681 / 1600
1+ r/100 = 41 / 40
r = 2.5
Therefore, SI = 5000 * 2 * 2.5 / 100 = Rs. 250
Question 9 |
rule | command | dictate |
doze | sleep | ? |
A | Govern |
B | Awaken |
C | Snoar |
D | Hibernate |
Question 9 Explanation:
The words above the line show a continuum: Command is more extreme than rule, and dictate is more extreme than command. Below the line, the continuum is as follows: Sleep is more than doze, and hibernate is more than sleep. The other choices are not related in the same way.
Question 10 |
A piece of ribbon 4 yards long is used to make a bow requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?
A | 11 |
B | 9 |
C | 10 |
D | 8 |
Question 10 Explanation:
To find maximum number of bows that can be made
1 yard = 36 inches
4 yards = 4*36=144 inches
No.of maximum bows that can be made = 144/15 = 9.6
So maximum 9 bows can be made
1 yard = 36 inches
4 yards = 4*36=144 inches
No.of maximum bows that can be made = 144/15 = 9.6
So maximum 9 bows can be made
Question 11 |
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A | 45 km/hr |
B | 50 km/hr |
C | 55 km/hr |
D | 54 km/hr |
Question 11 Explanation:
Speed of the train relative to man = (125 / 10)
= (25/2) m/sec
= (25 / 2 * 18 / 5) km/hr
= 45 km/hr
Let the speed of the train be x km/hr
Then, relative speed = (x - 5) km/hr
x - 5 = 45 => x = 50 km/hr
= (25/2) m/sec
= (25 / 2 * 18 / 5) km/hr
= 45 km/hr
Let the speed of the train be x km/hr
Then, relative speed = (x - 5) km/hr
x - 5 = 45 => x = 50 km/hr
Question 12 |
In the series 2, 6, 18, 54,.... what will be the 8th term ?
A | 4370 |
B | 7443 |
C | 4374 |
D | 7434 |
Question 12 Explanation:
Clearly, 2 x 3 = 6, 6 x 3 = 18, 18 x 3 = 54,....
. So, the series is a G.P. in which a = 2, r = 3.
Therefore 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374.
. So, the series is a G.P. in which a = 2, r = 3.
Therefore 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374.
Question 13 |
Three pipes A,B, C are attached to a tank. A and B can fill it in 20 and 30 minutes respectively while C can empty it in 15 minutes. If A,B and C are kept open successively for 1 minutes each, how soon will the tank be filled?
A | 167 minutes |
B | 180 minutes |
C | 200 minutes |
D | 178 minutes |
Question 13 Explanation:
Part of the tank filled in 3 minutes = (1/20) + (1/30) – (1/15) = 1/60
Part filled in 165 minutes = (165/3) * (1/60) = 55/60
Part filled in 167 minutes = (55/60) + (1/20) + (1/30) = 60/60 = 1
The tank is filled in 167 minutes
Part filled in 165 minutes = (165/3) * (1/60) = 55/60
Part filled in 167 minutes = (55/60) + (1/20) + (1/30) = 60/60 = 1
The tank is filled in 167 minutes
Question 14 |
In a can, there is a mixture of milk and water in the ratio 4:5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6:5. Find the capacity of the can?
A | 44 |
B | 52 |
C | 48 |
D | 40 |
Question 14 Explanation:
Let the capacity of the can be T litres
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44
Question 15 |
( 0.0203 * 2.92 ) / ( 0.0073 * 14.5 * 0.7 ) = ?
A | 0.8 |
B | 1.45 |
C | 3.25 |
D | 2.4. |
Question 15 Explanation:
(0.0203 x 2.92) / (0.0073 x 14.5 x 0.7) = (203 x 292) / (73 x 145 x 7) = 4/5 = 0.8
Question 16 |
Statement:
Quality of life of a person is not dependent only on his wealth.
Assumptions
I) The aim of most people is just to acquire more wealth.
II) There are some factors other than wealth which contribute to the quality of life.
III) Wealth does not contribute to the quality of life at all.
A | Only II is implicit |
B | Only I implicit |
C | Only I and II are implicit |
D | Only II and III are implicit |
E | Only I is implicit |
Question 16 Explanation:
Clearly, I does not follow from the statement.
So, it is not implicit. The statement mentions that quality of life does not depend only on wealth.
This means that there are some other factors as well, which govern the quality of life.
But this does not imply that wealth does not contribute at all. So, II is implicit while III is not.
So, it is not implicit. The statement mentions that quality of life does not depend only on wealth.
This means that there are some other factors as well, which govern the quality of life.
But this does not imply that wealth does not contribute at all. So, II is implicit while III is not.
Question 17 |
S1. The fragile Yugoslav state has an uncertain future.
A. Thus, there will surely be chaos and uncertainty if the people fail to settle their differences.
B. Sharp ideological differences already exist in the country.
C. Ethnic, regional, linguistic and material disparities are profound.
D. The country will also lose the excellent reputation it enjoyed in the international area.
S6. At worst, it will once more become vulnerable to international conspiracy and intrigue.
A | ADCB |
B | BACD |
C | ACBD |
D | BCAD |
Question 17 Explanation:
The proper order of the four sentences is BCAD
Question 18 |
The sum of the ages of A and B is 45 years. Five years ago, the product of their ages was four times the age of A at that time. The present ages of A and B, Respectively are?
A | 25 years |
B | None of these |
C | 36 years |
D | 39 years |
Question 18 Explanation:
A+B=45
(A-5)(B-5) = 4(A-5)
B - 5 = 4
B = 9 A = 36
B - 5 = 4
B = 9 A = 36
Question 19 |
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minutes. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A | 1800 |
B | 1964 |
C | 1500 |
D | 1600 |
Question 19 Explanation:
Let the required number of bottles be x
More machines, more bottles(direct proportion)
Machines = 6: 10 ::270 : x
Time(in minutes) = 1:4 :: 270 : x
6 * 1* x= 10* 4* 270
X= (10*4*270) / (6*1)
= 20 * 90
X = 1800
Question 20 |
Cara, a blue whale participated in a weight loss program at the biggest office. At the end of every month, the decrease in weight from original weight was measured and noted as 1, 2,6,21,86,445,2676. While Cara made a steadfast effort, the weight machine showed an erroneous weight once. What was that?
A | 2676 |
B | 86 |
C | 2 |
D | 445 |
Question 20 Explanation:
This is a number series problem
1, 2,6,21,86,445,2676
The wrong term has to be found out
1 *1+1 = 2
2*2 + 2 = 6
6*3+3 = 21
21*4+4 =88
88*5+5 =445
Hence, 86 is wrong. It should be 88
1, 2,6,21,86,445,2676
The wrong term has to be found out
1 *1+1 = 2
2*2 + 2 = 6
6*3+3 = 21
21*4+4 =88
88*5+5 =445
Hence, 86 is wrong. It should be 88
Question 21 |
A start a business investing Rs.40000.B joins him after 4 months. After a year, they divide the profit earned in the ratio of 6:5. How much did B invest?
A | Rs. 50000 |
B | Rs. 60000 |
C | Rs. 48000 |
D | Rs. 45000 |
Question 21 Explanation:
[(12*40000)/8x] = 6/5
Solving the equation, x = Rs. 50000
Solving the equation, x = Rs. 50000
Question 22 |
A vender by selling 12 toffee for a rupee. A man loses 20%. How many for a rupee should he sell to get a gain of 20%?
A | 12 |
B | 20 |
C | 10 |
D | 8 |
Question 22 Explanation:
12 toffee for rs 1 loss 20% then
C.P = 1 * 100/80 = 5/4 on this price we have to gain profit of 20%
So, 5/4 * 120/100 = 3/2
If for Rs. 2/3 we have 12 toffee then for rs 1 we have
= 12 x 2/3
= 8
C.P = 1 * 100/80 = 5/4 on this price we have to gain profit of 20%
So, 5/4 * 120/100 = 3/2
If for Rs. 2/3 we have 12 toffee then for rs 1 we have
= 12 x 2/3
= 8
Question 23 |
Writing ?
A | Pen |
B | Author |
C | Novel |
D | Skills |
Question 23 Explanation:
Explanation: The activity or occupation of composing text for publication.
Question 24 |
Statements:
I) A huge truck overturned on the middle of the road last night
II) The police had cordoned of entire area in the locality this morning for half of the day
A | Both the statement I and II are effects of some common cause |
B | Both the statement I and II are effects of independent causes |
C | Statement II is the cause and statement I is its effect |
D | Statement I is the cause and statement II is its effect |
E | Both the statement I and II are independent causes |
Question 24 Explanation:
Since a huge truck overturned on the middle of the road last night
so, the police had cordoned off the entire area in the locality last morning for half of the day
so, the police had cordoned off the entire area in the locality last morning for half of the day
Question 25 |
P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
A | 9(2/5) days |
B | 9(3/5) days |
C | 10 days |
D | 9(1/5) days |
Question 25 Explanation:
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
Question 26 |
If A + B means A is the mother of B; A - B means A is the brother B; A % B means A is the father of B and A x B means A is the sister of B, which of the following shows that P is the maternal uncle of Q?
A | Q - S % P |
B | P - M + N x Q |
C | P + S x N - Q |
D | Q - N + M x P |
Question 26 Explanation:
• P - M → P is the brother of M
• M + N → M is the mother of N
• N x Q → N is the sister of Q
Therefore, P is the maternal uncle of Q.
• M + N → M is the mother of N
• N x Q → N is the sister of Q
Therefore, P is the maternal uncle of Q.
Question 27 |
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
A | 42, 33 |
B | 41, 32 |
C | 39, 30 |
D | 43, 34 |
Question 27 Explanation:
Let their marks be (x + 9) and x.
Then, x + 9 = 56/100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Then, x + 9 = 56/100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Question 28 |
There has been bad blood between the two communities even before shouting.
A | Ill feeling |
B | Impure blood |
C | Bloody fights |
D | Quarrels |
Question 29 |
Find the odd man out 396, 462, 572, 427, 671, 264, ?
A | 396 |
B | 671 |
C | 427 |
D | 264 |
Question 29 Explanation:
In each number except 427, the middle digit is the sum of other two
Question 30 |
Between June 1990 and February 1993, how many months have 31 days ?
A | 17 |
B | 19 |
C | 18 |
D | 20 |
Question 30 Explanation:
In a year, 7 months have 31 days
From Jun ’90 to Feb ‘93
(4 in ‘90) + (7 in ‘91) + (7 in ‘92) + (1 in ‘93) = 19
From Jun ’90 to Feb ‘93
(4 in ‘90) + (7 in ‘91) + (7 in ‘92) + (1 in ‘93) = 19
Question 31 |
I) Tom puts on his socks before he puts on his shoes.
II) He puts on his shirt before he puts on his jacket.
III) Tom puts on his shoes before he puts on his shirt.
If the first two statements are true, the third statement is
A | Uncertain |
B | False |
C | True |
Question 31 Explanation:
There is not enough information to verify the third statement
Question 32 |
A 6% stock yields 8%. The market value of the stock is
A | Rs. 75 |
B | Rs. 133.33 |
C | Rs. 96 |
D | Rs. 48 |
Question 32 Explanation:
For an income of Rs. 8, Investment = Rs. 100
For an income of Rs. 6, investment = Rs. 100/8 * 6
= Rs. 75
Market value of Rs. 100 stock = Rs. 75
Question 33 |
The fourth proportional to 5, 8, 15 is ?
A | 18 |
B | 19 |
C | 20 |
D | 24 |
Question 33 Explanation:
Let the fourth proportional to 5, 8, 15 be x
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = (8 x 15) / 5 = 24
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = (8 x 15) / 5 = 24
Question 34 |
If tee see pee means drink fruit juice, see kee lee means juice is sweet, and lee ree mee means he is intelligent, which word in that language means sweet?
A | lee |
B | kee |
C | tee |
D | pee |
E | see |
Question 34 Explanation:
In the first and the second statements the common word is juice and the common code word is see. So see means juice. In the second and the third statements, the common word is ‘is’ and the common code is lee. So lee means is. Thus in the second statement, the remaining word sweet is coded as kee. Hence the answer is (2).
Question 35 |
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
A | 75 |
B | 65 |
C | 85 |
D | 60 |
Question 35 Explanation:
since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = 551/29 = 19; Third number = 1073/29 = 37.
Required sum = (19 + 29 + 37) = 85.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = 551/29 = 19; Third number = 1073/29 = 37.
Required sum = (19 + 29 + 37) = 85.
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