[vc_row][vc_column][vc_toggle title=”Explanation / Important formulas:” el_id=”1481454282462-60885454-0285″]
Series completion section deals with questions in which series of numbers are given, which are generally called as terms of the series. These terms follow a certain pattern throughout.
The candidate is required to recognize this pattern and either complete the given series with the most suitable alternative or find wrong in the series.
- Number series tests present numerical sequences that follow a logical rule which is based on elementary arithmetic.
- The difficulty level of these questions can increase in two ways; first, the logic behind the sequence becomes less trivial and demands attention and creativity; second, the missing number can be positioned at an early stage, thus preventing you from deciphering the hidden rule by looking only at the previous numbers in the sequence.
[/vc_toggle][vc_toggle title=”Instructions to take Aptitude Test” el_id=”1481454372988-cd8f0f96-30f0″]
- Click on start to start taking the test.
- Click on the option (A, B, C or D) to figure out the right answer.
- You can answer multiple times till you get the right answer.
- Once you get the right answer, explanations (if any) for the same will be showcased down.
- On click of list, you get to see total no of questions, no of questions you answered and no of questions pending to answer.
- On click of question number you will go to that particular question.
- On click of END your test will end.
- On click of ‘Get Results’ you will get to see correct answer for each questions.
[/vc_toggle][vc_toggle title=”Series Completion – Test” el_id=”1481454458410-9a4a39ac-c8b7″]
Series Completion - Question and Answers
Question 1 |
35 | |
38 | |
39 | |
40 |
So, missing term = 48 - 13 = 35.
Question 2 |
58965 | |
65423 | |
89654 | |
96542 |
Question 3 |
10101 | |
10201 | |
10202 | |
11012 |
So, missing term = 1012 + 1 = 10202.
Question 4 |
4370 | |
4374 | |
7443 | |
7434 |
. So, the series is a G.P. in which a = 2, r = 3.
Therefore 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374.
Question 5 |
5 | |
8 | |
10 | |
12 |
So, missing term = 20 - 15 = 5.
Question 6 |
18 | |
27 | |
36 | |
81 |
So, missing term = 18 x 3/2 = 27.
Question 7 |
201 | |
202 | |
203 | |
205 |
So, missing term = 101 x 2 + 1 = 203.
Question 8 |
21 | |
25 | |
27 | |
33 |
So, missing term = 15 + (1 + 2 + 3 + 4) = 25.
Question 9 |
37 | |
44 | |
50 | |
55 |
So, missing number = 8 + 15 + 27 = 50.
Question 10 |
42 | |
43 | |
52 | |
53 |
I. 3, 7, 13, 21, 31, ? and II. 4, 7, 13, 22, 34
The pattern in I is + 4, + 6, + 8, + 10,.....
The pattern in II is + 3, + 6, + 9, + 12,.....
So, missing term = 31 + 12 = 43.
Question 11 |
92 | |
112 | |
136 | |
144 |
So, missing pattern = 169 - 52 = 169 - 25 = 144.
Question 12 |
33 | |
38 | |
40 | |
45 |
So, missing term = 21 + 12 = 33.
Question 13 |
10th | |
9th | |
8th | |
None of these |
So, the series is a G.P. in which a = 5 and r = 2.
Let 1280 be the rath term of the series.
Then, 5x2n-1 = 1280 2n-1 = 256 = 28 n - 1 = 8 n = 9.
Question 14 |
14 | |
16 | |
18 | |
24 |
So, missing term = 9 + 5 = 14.
Question 15 |
23 | |
38 | |
39 | |
40 |
So, missing term = 13 x 3 = 39.
Question 16 |
316 | |
1135 | |
1288 | |
2254 |
So, missing term = 1127 + 8 = 1135.
Question 17 |
9 | |
10 | |
11 | |
12 |
III. 3rd, 6th, 9th, 12th terms i.e. 2, 5, 8, 11
Clearly, I consists of consecutive even numbers. So, the missing term is 10.
Question 18 |
256 | |
512 | |
729 | |
1000 |
Question 19 |
45 | |
52 | |
54 | |
55 |
I. 13, 24, 35, 46, 57 and II. 32, 43, ?, 65, 76
The pattern in both I and II is + 11. So, missing term = 43 + 11 = 54.
Question 20 |
27 | |
35 | |
45 | |
56 |
So, missing term = (62 - 1) - (36 - 1) = 35.
Question 21 |
150 | |
175 | |
225 | |
250 |
So, missing term = 3 x 50 = 150.
Question 22 |
76 | |
90 | |
96 | |
98 |
So, missing term = 192 ÷ 2 = 96.
Question 23 |
111 | |
120 | |
121 | |
132 |
So, missing term = 80 + 52 = 132.
Question 24 |
42 | |
51 | |
81 | |
91 |
So, missing term = 56 + 25 = 81.
Question 25 |
672 | |
386 | |
279 | |
143 |
So, missing term = 815 - (84 x 23) = 815 - 672 = 143.
Question 26 |
1110 | |
1112 | |
1113 | |
1315 |
odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, .....
So, missing term = number formed by joining 11 and 13 = 1113.
Question 27 |
64 | |
86 | |
94 | |
122 |
So, missing term = 46 + 48 = 94.
Question 28 |
3 | |
6 | |
8 | |
9 |
So, missing term = 1 x 8 = 8.
Question 29 |
117 | |
121 | |
123 | |
129 |
So, the series is an A.P. in which a = 3 and d = 6.
Therefore 21st term = a + (21 - 1) d = a + 20d = 3 + 20 x 6 = 123.
Question 30 |
32 | |
34 | |
38 | |
40 |
So, missing term = 36 - 2 = 34.
Question 31 |
64 | |
81 | |
91 | |
100 |
i.e. 12, 32, 52, 72,.....
So, missing term = 92 = 81.
Question 32 |
49 | |
50 | |
51 | |
52 |
So, missing term = 28 + (52 - 1) = 28 + 24 = 52.
Question 33 |
20 | |
23 | |
24 | |
25 |
So, missing term = 14 + 10 = 24.
Question 34 |
48 | |
346 | |
574 | |
1003 |
Question 35 |
180 | |
240 | |
420 | |
480 |
So, missing term = 240 ÷ 1 = 240
Question 36 |
226 | |
339 | |
452 | |
565 |
So, missing term = 112 x 5 + 5 = 565.
Question 37 |
83 | |
94 | |
116 | |
127 |
So, missing term = 72 + 44 = 116.
Question 38 |
10, 10 | |
10, 11 | |
13, 14 | |
13, 16 |
Thus, the sequence 20, 20, 19, 16, 17, 13, 14, 11, xv x2 is a combination of two series :
I. 20, 19, 17, 14, x1 and II. 20, 16, 13, 11, x2
The pattern in I is - 1, - 2, - 3,......So, missing term, x1 = 14 - 4 = 10.
The pattern in II is - 4, - 3, - 2,......So, missing term, x2 = 11 - 1 = 10.
Question 39 |
400 | |
410 | |
420 | |
430 |
So, missing term = 310 + 120 = 430.
Question 40 |
101 | |
110 | |
111 | |
None of these |
So, missing term = 10 x 10 + 1 = 101.
Question 41 |
1262 | |
1707 | |
4027 | |
4207 |
So, missing term = 427 + (5 x 162) = 427 + 1280 = 1707.
Question 42 |
50 | |
51 | |
52 | |
53 |
5^2-1 = 28 + 24
= 52
Question 43 |
24 | |
28 | |
31 | |
33 |
Missing Number = 19+9 = 28
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