[vc_row][vc_column][vc_toggle title=”Important Formulas / Properties:” el_id=”1481453524397-6409ba7b-b187″]Consider x, as the age of an individual
- If the current age of the person is x, then n times the age is nx
- If the current age of the person is y, then age n years ago = y – n
- If the current age of the person is z, then age n years later = z + n
- The age of the person in a ratio a: b will be ax and bx
- If the current age of the person is s , then 1/n of the age is s/n
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[/vc_toggle][vc_toggle title=”Question and Answers” open=”true” el_id=”1481453735500-52d42176-167e”]
Ages - Question and Answers - Question and Answers
Question 1 |
18 | |
25 | |
15 | |
20 |
S = 30
S - 10 = 2(A - 10)
A = 20
Question 2 |
9:2 | |
12:5 | |
11:3 | |
13:4 |
4D - M = 3
M + 6 = 2(D+6)+9
M - 2D = 15
Solving,
2D = 18
D = 9
M = 33
M : D = 11 : 3
Question 3 |
12 yrs | |
15 yrs | |
19 yrs | |
21 yrs |
J - N = 4 : 3
N = 15
Question 4 |
25 years | |
39 years | |
36 years | |
None of these |
B - 5 = 4
B = 9 A = 36
Question 5 |
20 | |
24 | |
30 | |
None of these |
2J = A + P
A + P = 48
2J = 48
J = 24
Question 6 |
1 year | |
2 year | |
25 year | |
Data Inadequate |
(R+T) = 2Q
Now given that, (R+T) = 50
2Q = 50
Q = 25
Without knowing the value of R or T, we cant find R -Q. Hence, Data inadequate
Question 7 |
The ratio of the age of pramond and the age of akash is 3:5 and sum of their ages is 80 years. The ratio of their ages after 10 years will be?
2:3 | |
1:2 | |
3:2 | |
3:5 |
3x + 5x = 80
8x = 80 ,x = 10
3x=30
5x=50
Ratio of theie age after 10 years = (3x+10) : (5x+10)
=> 40 : 60 = 2 : 3
Question 8 |
4:3 | |
12:11 | |
7:4 | |
6:5 |
M : N = 4 : 3
M + N = 28
4x + 3x = 28
X= 4
M= 16
N=12
(M+8) : (N+8) = 24 : 20 = 6 : 5
Question 9 |
16yrs | |
18 yrs | |
28 yrs | |
24.5 yrs |
S:R = 7:9
9S = 7R
9(R-7) = 7R
2R = 63
R = 31.5
S = 24.5
Question 10 |
4 | |
5 | |
6 | |
8 |
(m+4)(w+4) = 9 : 7
7(m+4) = 9(w+4)
28w/3 + 28 = 9w + 36
w/3 = 8
w = 24
m = 32
(32 - x)(24 -x) = 7 : 5
x = 4
Question 11 |
5:2 | |
10:3 | |
8:3 | |
9:4 |
(f + 2) = 3(s + 2)
Solving, s = 12 f = 40
F : S = 10 : 3
Question 12 |
A grandfather has 3 grand children. Age difference of the two younger children is 3. The age of the eldest child is 3 times the age of the youngest child and also two years more than the sum of the ages of the other two children. What is the age of the eldest child?
15 | |
10 | |
22 | |
18 |
X = y + z + 2
y - z = 3
solving the three equations, x = 15
Question 13 |
5 | |
10 | |
15 | |
20 |
X - Z = 10
Question 14 |
13 | |
15 | |
16 | |
18 |
(p - 6) = 3(q - 6)
p - 3q = -12 .....(2)
solving(1) and (2)
q = 13
Question 15 |
6 | |
7 | |
5 | |
4 |
His father’s age = x + 32
His sister’s age = x - 3
His mother’s age = x-3+29 = x+26
Difference between the ages of his parents = (x+32) -(x+26)
=> x = 6
Question 16 |
32 | |
35 | |
37 | |
40 |
Brother’s age = x+5
My sister is five years elder than my brother
Sister’s age = x+10
My father was 30 years of age when my sister was born
Father’s age = x+10+30 = x+40
My mother was 32 years of age when i was born Mother’s age = x+32
Father’s age when my brother was born = x+4(x+5) = 35
Question 17 |
12 | |
20 | |
24 | |
40 |
(3x-8)+(5x-8)+(8x-8) = 40
16x - 24 = 40
2x - 3 = 5
x = 8/2 = 4
B’s present age = 5x = 20
Question 18 |
48 | |
55 | |
49 | |
53 |
Year of R’s birth 1994 - x
Year of grandma’s birth 1994 - 2x
1994 - x + 1994 - 2x = 3844
3x = 3988 - 3844 = 144
x = 48
Age of R in 1999 = x+5 = 53
Question 19 |
29
| |
39 | |
48 | |
86 |
A = B+9
Solving two equations,
B+9 = 2B-20
B = 39
Question 20 |
10 | |
11 | |
15 | |
18 |
2A - 4 = N - 2
2A - 4 = A + 9 - 2
A = 11
Question 21 |
10
| |
15
| |
18 | |
20 |
(t+10) = (2/3) * (f+10)
3T + 30 = 2F + 20
2F - 3T = 10
2*(2T) - 3T = 10
T = 10
F = 2T = 20
Question 22 |
12
| |
11 | |
10 | |
6 |
(x-5)+(x-5) = (f-5)
X+m = f+5
X = f - m + 5
f - m = 6
x = 6+5 = 11
Question 23 |
1:3
| |
3:1
| |
1:2
| |
2:1 |
L+N = 2L-2N
3N = L
N/L = 1/3
N:L = 1:3
Question 24 |
20
| |
10 | |
18 | |
16 |
(B-2) = 2S-4
8+S-2 = 2S-4
S = 10
B = 18
Question 25 |
12
| |
15 | |
14 | |
9 |
deepa’s present age = 5x
(4x-4) : (5x-4) = 8:11
44x - 44 = 40x - 32
4x = 12
x = 3
4x = 12
Question 26 |
25
| |
33 | |
27 | |
30 |
Let the son’s present age be x years
The father was x years old when the son was born (before x years)
54 - x = x
x = 27
Question 27 |
35
| |
40 | |
38 | |
31 |
Father’s age = x+2.5x = 3.5x
(3.5x-5) = 6(x-5)
3.5x - 5 = 6x - 30
2.5x = 25
x = 10
Father’s present age = 35
Question 28 |
11
| |
14 | |
15 | |
10 |
daughter’s present age = x
3x*x = 363
3x2 = 363
X2 = 121
X = 11
Daughter’s age after 4 years = 15
Question 29 |
12
| |
18 | |
6 | |
15 |
sum of their ages before 5 years = 3x - 5 = 5x - 5 = 7x-5
15x - 15 = 60
Solving, x = 5
Age of the youngest = 3x = 15
Question 30 |
25 | |
22 | |
20 | |
27 |
A - B = C/6
B+C = 32
Solving the three equation, A = 22
Question 31 |
18 | |
19 | |
15 | |
21 |
(x+y)/2 = 21
x+y = 42
(x+y+z)/3 = 19
x+y+z = 57
42+z = 57
z = 15
Question 32 |
30 | |
39 | |
26 | |
27 |
(K + D) /2 = 29
Solving, k = 25, D = 33
K+5 = 30
Question 33 |
20 | |
25 | |
28 | |
30 |
S = M+5
A+S+M = 73
S+3+S+S-5 = 73
S = 25
Question 34 |
16 | |
20 | |
21 | |
25 |
x-y = 7
x-5 = 2(y-5)
solving the two linear equations
y = 12, y+4 = 16
Question 35 |
10 | |
12 | |
15 | |
20 |
(V/N) = (5/3)
Solving the two equations, N = 12
Question 36 |
23 years | |
21 years | |
33 years | |
25 years |
X+1 = 2(x=10)
Solving, x = 21
Question 37 |
8 | |
9 | |
12 | |
6 |
Shyams present age = 2x
2x-3 = 3(x-3)
x = 6
Question 38 |
48 years | |
42 years | |
70 years | |
84 years |
(x/6)+(x/12)+(x/7)+5+y+4 = x
x = 2y
By solving, x = 84
Question 39 |
36 | |
42 | |
45 | |
48 |
F+15 = 2(S+15)
By solving equation, F = 45
Question 40 |
360 | |
240 | |
120 | |
480 |
F = 2N+40
F+N+S = 1240
Solving these, N = 360
Question 41 |
18 | |
16 | |
11 | |
9 |
(x+5)+(y+5)+(z+5) = 41
x+y+z = 26
By trial and error method, their ages are 1,9 and 16
The age of his eldest daughter after 2years is 18
Question 42 |
58 | |
46 | |
28 | |
30 |
y-13 = 3(x-13)
y-2 = 2(x-2)
by solving equation, y = 46
Question 43 |
6 | |
9 | |
11 | |
4 |
F-R = 29
By solving two equations, R = 6
Question 44 |
27 | |
30 | |
33 | |
36 |
F+3 = 6(S+3)
M/S = 10
Solving these equations, f = 33
Question 45 |
25 | |
20 | |
15 | |
16 |
L = B+4
R+L+B = 61
Solving the three equations, L = 20
Question 46 |
4 | |
6 | |
8 | |
2 |
Let the age of the siblings be y and y+4
X+6-y = 33
(x+x+6+y+y+4)/4 = 20
Solving the equations, y = 4
Question 47 |
14 | |
12 | |
8 | |
6 |
H+2 = 2*(K+2)
By solving equation , k = 6
Question 48 |
2 | |
4 | |
6 | |
8 |
3x = 2x+3
A = 2x = 6
B = 3x = 9
Age of A after 2 years is 8