Instructions for **Aptitude Contest**** – June 2020****:**

- You can select only one option at a time.
- You can take the QUIZ multiple times.
- Each question will carry 100 points.
- There are altogether 28 questions.
- After finishing the test, you will get a score message as shown below.
- If you score more than 90% you will get a unique code and email id along with the score message.
- Take the screenshot of the entire page containing the message along with the unique code generated.
- Lucky winners will get
**exciting goodies/gift**from JUMPWHERE. The final decision will be taken by JUMPWHERE TEAM itself. - This contest is available only till 30-June-2020 12:00 PM.
- Don’t forget to Like and Follow us on facebook for all the updates.

** Aptitude Contest**** – June 2020:**

## Quiz Contest - June 2020

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*Quiz Contest - June 2020*. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%
Your answers are highlighted below.

Question 1 |

Find the ratio between the speeds of the boat and stream if the boat can travel 30 km upstream in 3 hours and the same distance downstream in 2 hours?

A | 20 m cube |

B | 50 m cube |

C | 100 m cube |

D | 10 m cube |

Question 1 Explanation:

Volume of the cylinder = π r square h = 550 m cube

Volume of the cuboid = 550/11 = 50 m cube

Volume of the cuboid = 550/11 = 50 m cube

Question 2 |

Which of the following years will have a calendar similar to the year 2011?

A | 2016 |

B | 2020 |

C | 2022 |

D | 2017 |

Question 2 Explanation:

No. of odd days from 2011 to 2022

= 1+2+1+1+1+2+1+1+1+2+1

= 14

Hence, 2022 will have a calendar similar to 2011

The number of odd days increases from 6 to 8 since 2016 is a leap year

Hence 14 odd days are calculated

= 1+2+1+1+1+2+1+1+1+2+1

= 14

Hence, 2022 will have a calendar similar to 2011

The number of odd days increases from 6 to 8 since 2016 is a leap year

Hence 14 odd days are calculated

Question 3 |

Find the odd man out 3, 5, 7, 12, 17, 19?

A | 17 |

B | 19 |

C | 5 |

D | 12 |

Question 3 Explanation:

Each of the numbers is a prime number except 12.

Question 4 |

All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?

A | 888 |

B | 928 |

C | 648 |

D | 1184 |

Question 4 Explanation:

B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k

Quantity of water in B = 8k - 5k = 3k

Quantity of water in container C = 8k - 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water

5k - 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 litres

Quantity of water in B = 8k - 5k = 3k

Quantity of water in container C = 8k - 3k = 5k

Container: A B C

Quantity of water: 8k 3k 5k

It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water

5k - 148 = 3k + 148 => 2k = 296 => k = 148

The initial quantity of water in A = 8k = 8 * 148 = 1184 litres

Question 5 |

A pipe can fill a tank in an hour. Because of a leak, it took 1 hour and 10 minutes to fill the tank. Find the time taken by the leak to drain all the water in the tank?

A | 6/7 hrs |

B | 7/6 hrs |

C | 7 hrs |

D | 10 mins |

Question 5 Explanation:

Let the leak take x to drain the tank
1hr 10 min = 1+(1/6) = 7/6 hrs

1- (1/x) = 1/ (7/6) = 6/7

Part of tank leaked in an hour = 1-6/7 = 1/7

The leak takes7 hours to drain all the water

1- (1/x) = 1/ (7/6) = 6/7

Part of tank leaked in an hour = 1-6/7 = 1/7

The leak takes7 hours to drain all the water

Question 6 |

A | 15 |

B | 20 |

C | 25 |

D | 17 |

Question 6 Explanation:

17 persons take tea and wine but not coffee

Question 7 |

Read the each sentence to find out whether there is any grammatical error in it. The error, if any will be in one part of the sentence. The letter of that part is the answer. If there is no error, the answer is 'E'. (Ignore the errors of punctuation, if any).
(solve as per the direction given above)

A | Even after requesting |

B | he wolved the problem |

C | tell us that how |

D | him, he did not |

E | No error |

Question 7 Explanation:

tell us how

Question 8 |

A can do a particular work in 6 days. B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C?

A | 600 |

B | 400 |

C | 380 |

D | 420 |

Question 8 Explanation:

Amount of work A can do in 1 day = 1/6

Amount of work B can do in 1 day = 1/8

Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24

Amount of work A + B + C can do = 1/3

Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24

Work A can do in 1 day : work B can do in 1 day : work C can do in 1 day

= 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Amount to be paid to C = 3200 * (1/8) = 400

Amount of work B can do in 1 day = 1/8

Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24

Amount of work A + B + C can do = 1/3

Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24

Work A can do in 1 day : work B can do in 1 day : work C can do in 1 day

= 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Amount to be paid to C = 3200 * (1/8) = 400

Question 9 |

A, B and C invest Rs.50000, Rs.75000 and Rs. 125000 in a business respectively. The profit earned is Rs.20000. Find the profit share of B

A | Rs. 2000 |

B | Rs. 10000 |

C | Rs. 6000 |

D | Rs. 4000 |

Question 9 Explanation:

Ratio of the share of A, B and C = 50000: 75000:12500
= 2:3:5

B’s share of profit = (3/10)*20000 = Rs. 6000

B’s share of profit = (3/10)*20000 = Rs. 6000

Question 10 |

While the ladies continued their

*small talk*in the drawing room, I felt bored.A | whispering |

B | gossip |

C | light conversation |

D | backbiting |

Question 11 |

PLAIN : AUSTERE :: ?

A | deserted : barren |

B | clean : sterile |

C | lonely : gloomy |

D | neutral : detached |

Question 11 Explanation:

(DEGREE OF INTENSITY) Being austere (meaning bare) is a heightened form of being plain; being sterile (meaning free from bacteria or other micro-organisms) is a heightened form of being clean. {The pairs (neutral, detached); (deserted, barren) and (eloquent, talkative) are mere synonyms.} (B)

Question 12 |

Find the ratio between the speeds of the boat and stream if the boat can travel 30 km upstream in 3 hours and the same distance downstream in 2 hours?

A | 5:1 |

B | 4:1 |

C | 2:3 |

D | 3:2 |

Question 12 Explanation:

U = 10 kmph

D= 15 kmph

S= (d - u) / 2 = 2.5 kmph

B= (d + u)/2 = 12.5 kmph

b:s = 5:1

D= 15 kmph

S= (d - u) / 2 = 2.5 kmph

B= (d + u)/2 = 12.5 kmph

b:s = 5:1

Question 13 |

BRIEF

A | Limited |

B | Little |

C | Small |

D | Short |

Question 13 Explanation:

BRIEF means a short and concise statement or written item. 6. an outline, the form of which is determined by set rules, of all the possible arguments and information on one side of a controversy: a debater's brief.

Question 14 |

1.at 2.it 3.take 4.once 5.away

A | 53214 |

B | 42315 |

C | 14352 |

D | 23514 |

E | 32514 |

Question 14 Explanation:

Explanation : " Take it away at once "

Question 15 |

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

A | 10:30 am |

B | 11 am |

C | 10 am |

D | 9 am |

Question 15 Explanation:

Suppose they meet x hours after 7 a.m

Distance covered by A in x hours = 20xkm

Distance covered by B in (x - 1) hours = 25(x - 1) km

20x + 25(x - 1) = 110 45x = 135 x = 3.So, they meet at 10 a.m

Distance covered by A in x hours = 20xkm

Distance covered by B in (x - 1) hours = 25(x - 1) km

20x + 25(x - 1) = 110 45x = 135 x = 3.So, they meet at 10 a.m

Question 16 |

What is the unit digit in 7

^{105}?A | 9 |

B | 7 |

C | 1 |

D | 5 |

Question 16 Explanation:

Unit digit in 7

But, unit digit in (7

Unit digit in 7

^{105}= Unit digit in [ (7^{4})^{26}x 7 ]But, unit digit in (7

^{4})^{26}= 1Unit digit in 7

^{105}= (1 x 7) = 7Question 17 |

617 + 6.017 + 0.617 + 6.0017 =

A | 6.2963 |

B | 629.6357 |

C | None of these |

D | 62.965 |

Question 17 Explanation:

617.00

6.017

0.617

+ 6.0017

--------

629.6357

---------

6.017

0.617

+ 6.0017

--------

629.6357

---------

Question 18 |

CONCEDE

A | Accede |

B | Grant |

C | Object |

D | Refuse |

Question 18 Explanation:

CONCEDE means admit or agree that something is true after first denying or resisting it.

Question 19 |

**Broken Reed?**

A | Continue support |

B | None of the above |

C | Support endlessly |

D | Support that failed |

Question 19 Explanation:

Example : In the time of need, his friend proved a broken reed.

Question 20 |

In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?

A | 5/7 |

B | 1/10 |

C | 2/5 |

D | 2/7 |

Question 20 Explanation:

P(getting a prize) = 10/(10+25) = 10/35 = 2/7

Question 21 |

Who is at the extreme left end?
Read the following information carefully and answer the question
given above

- There are five friends
- They are standing in a row facing south.
- Jayesh is to the immediate right to Alok.
- Pramod is between Bhagat and Subodh.
- Subodh is between Jayesh and Pramod.

A | Alok |

B | Bhagat |

C | Subodh |

D | Data Inadequate |

Question 21 Explanation:

The boys are standing facing south. So, consider left and right accordingly.

Jayesh is to the right of Alok i,e Jayesh, Alok.

Pramod is between Bhagat and Subodh i,e Bhagat, Pramod, Subodh

Subodh is between Jayesh and Pramod.

So, the sequence is Bhagat Pramod Subodh Jayesh Alok

Answer for this question is (a), Alok is at extreme left end

Jayesh is to the right of Alok i,e Jayesh, Alok.

Pramod is between Bhagat and Subodh i,e Bhagat, Pramod, Subodh

Subodh is between Jayesh and Pramod.

So, the sequence is Bhagat Pramod Subodh Jayesh Alok

Answer for this question is (a), Alok is at extreme left end

Question 22 |

**S1. Figure skating is primarily a sport of amateurs.**A. For years, the singles competition was judged according to two categories. B. The compulsory – figures category required each skater to perform three or six repetitions of three figures drawn from a possible 41 patterns. C. Contests are held for singles and for pairs. D. The free – skating category judged a skater’s ability to perform jumps, spins, spirals, and skating coordinated with music.

**S6. All figures are based on a figure – eight pattern or variations thereof.**

A | CADB |

B | CDBA |

C | BCAD |

D | ABCD |

Question 22 Explanation:

The proper order for the four sentences is CADB

Question 23 |

Arrange the words given below in a meaningful sequence.

- Heel 2. Shoulder 3. Skull 4. Neck 5. Knee 6. Chest 7. Thigh 8. Stomach 9. Face 10. Hand.

A | 4,7,10,1,9,6,2,5,8,3 |

B | 3,4,7,9,2,5,8,18,6,1 |

C | 2,4,7,10,1,5,8,9,6,3 |

D | 3,9,4,2,10,6,8,7,5,1 |

Question 23 Explanation:

The correct order is:

Skull Face Neck Shoulder Hand Chest Stomach Thigh Knee Heel

3 9 4 2 10 6 8 7 5 1

Skull Face Neck Shoulder Hand Chest Stomach Thigh Knee Heel

3 9 4 2 10 6 8 7 5 1

Question 24 |

**Statement**: Company X has a record of manufacturing cameras of quality and the latest design so that you do not spoil even a single shot irrespective of the weather conditions.

**Conclusions : **

##### I. No other company except X is reputed in camera industry.

##### II. Acceptable shot with camera of company X can be taken in any weather conditions.

A | Neither I nor II follows |

B | Both I and II follow |

C | Only Conclusion I follows |

D | Either I or II follows |

E | Only Conclusion II follows |

Question 24 Explanation:

Only Conclusion II follows

Question 25 |

The ratio of the age of pramond and the age of akash is 3:5 and sum of their ages is 80 years. The ratio of their ages after 10 years will be?

A | 1:2 |

B | 3:2 |

C | 2:3 |

D | 3:5 |

Question 25 Explanation:

Let the ages of pramod and akash be 3x and 5x

3x + 5x = 80

8x = 80 ,x = 10

3x=30

5x=50

Ratio of theie age after 10 years = (3x+10) : (5x+10)

=> 40 : 60 = 2 : 3

3x + 5x = 80

8x = 80 ,x = 10

3x=30

5x=50

Ratio of theie age after 10 years = (3x+10) : (5x+10)

=> 40 : 60 = 2 : 3

Question 26 |

**Statements:**Some cows are crows. Some crows are elephants.

**Conclusions:**I) Some cows are elephants. II) All crows are elephants.

A | Either I or II follow |

B | Only Conclusion II follows |

C | Neither I nor II follow |

D | Only Conclusion I follows |

Question 27 |

Code of diplomatic etiquette and precedence?

A | Protocol |

B | Statesmanship |

C | Formalism |

D | Hierarchy |

Question 27 Explanation:

Protocol means the official procedure or system of rules governing affairs of state or diplomatic occasions.

Question 28 |

If I

**had the address**, I would have delivered the package myselfA | had had the address, |

B | had the address - |

C | had had the address |

D | had the address; |

E | had the address, |

Question 28 Explanation:

Since this entire conditional-subjunctive sentence construction is in the past, the correct conditional form is past perfect "If I had had" rather than present perfect "if I had" [(A), (B), (C)] with the present perfect subjunctive "I would have."

The correct punctuation between conditional "if" and subjunctive "would" parts is always a comma, never a semicolon [(B), (D)] or a dash (C).

The correct punctuation between conditional "if" and subjunctive "would" parts is always a comma, never a semicolon [(B), (D)] or a dash (C).

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